Math, asked by lalit9204272, 9 months ago

In an election wer only two candidates the wining candidates got 48%of the total votes his opponent got 6800 votes which represented 34%of the total votes find
a)the number of votes polled
b)the wining margin​

Answers

Answered by viditrana2007
1

Answer:

Winning candidate got 9600 votes and The winning margin is 2800.

Step-by-step explanation:

Let the total votes be x

Opponent received 34% votes

We are given that Opponent got votes = 6800

So,

Winning candidate got 48% of the total votes

Winning candidate got votes =

                                                =

Winning margin = winner votes - opponent votes

                             = 9600 - 6800

                            =2800

Hence Winning candidate got 9600 votes and  The winning margin is 2800.

Answered by vijaspandey
0

Answer:

Winning candidate got 9600 votes and  The winning margin is 2800.

Let the total votes be A

Opponent received 34% votes

=34% x A

= 34/100 x  A

We are given that Opponent got votes = 6800

so  , 68% = 34/100 x  A

         68 x 100 / 34 =  A

        20000 = A        

Winning candidate got 48% of the total votes

Winning candidate got votes    = 48 /100 X 20000

                                                     =  9600

Winning margin = winner votes - opponent votes

                            = 9600 - 6800

                           =2800

Hence Winning candidate got 9600 votes and  The winning margin is 2800.

hope it will help you...

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