Math, asked by moneyraaz, 10 months ago

In an election where there are only two candidates A and B, a survey was conducted to find out the
popularity of the contestants. It was found that 64% of the respondents favoured A as their leader while
the balance favoured B. In another poll conducted 2 days later, it was found that 25% of A's supporters
had shifted support to B, while 20% of B's supporters had shifted their support to A. What minimum
percentage of the total respondents must B now attract in order to tie with A?​

Answers

Answered by cashedjohnny123
0

Answer:

lemme try on a paper

let X be the total voters respond

then 64% of X= 0.64x people support candidate A

remaining % of voters= (100-64)%= 36%

then 36% of X= 0.36x people support candidate A

change in poll after 2 days

voters leaving A for B= 25% of 0.64x= 0.16x

voters leaving B for A= 20% of 36x= 0.072x

now A's total supporter= (0.64x-0.16x)+ 0.072= 0.552x

B's total supporters= (0.36x-0.072x)+0.16x= 448

votes require by B so that A and B are left with equal votes/supporter= (0.552x-0.448x)/2= 0.52x

thus, 0.52x votes should be removed from A supporter and add to B.

let y% be the require percentage of the total respondent B must acquire inorder to tie with A.

then,

= y% of X= 0.52x

y%= 0.52x/X

= 0.52%

hope this is the answer

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