Math, asked by rajshaktawat, 1 year ago

In an elections 10% of the voters on the voter's
list did not cast the votes and 60 voters cast
their ballot paper blank. There were only two
canditates. The winner was supported by 47%
of all the voters in the list and he got 308 votes
more than his rival. The number of voters on
the list was
एक चुनाव में 10 प्रतिशत मतदाताओं ने अपना मत नहीं दिया और 60
मतदाताओं ने मतपत्र को खाली छोड़ दिया। चुनाव में केवल 2 उम्मीदवार
हैं तथा जीतने वाले उम्मीदवार ने कुल मतों का 47 प्रतिशत प्राप्त
करके 308 वोट से जीत गया तो मतदाता सूची में कुल वोट कितने हैं?
plz solution made it with solution​

Answers

Answered by micky32
2

Answer:

it was 6200 voters hope you like my answer

Answered by mekanomangte
1

Step-by-step explanation:

Total votes be 100X

then 100x-10x {voter who did not cast vote is 10)

= 90x

winner loser

47x 43x

now,

47x - (43x-60)= 308 {60 votes cast their ballot blank}

4x+60 = 308

4x= 248

x= 62

therefore total vote is 100 X 62 = 6200

.. hope it helps

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