in an electric circuit 1X10 power of 8 hydrogen ions are travelling per second in right direction while double number of electrons are traveling pet second in the left direction in the total current through the path is... 1) 4.8A 2) 1A 3) 0.48A 4) 0.1A
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Answer:
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Explanation:
For Hydrogen ions,
I
1
=
8 19 Q ne 1 10 1.6 10
tt 1
-
´ ´´
= =
I
1
= 0.16 A
For electrons, I2
=
8 19 Q ne 2 1 10 1.6 10
tt 1
-
´´ ´ ´
= =
I2
= 0.32 A
As electrons move towards positive ions,
total current is addition of both currents
\ I = I = I1
+ I2
= 0.16 + 0.32 = 0.48 A
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