Question

in an electric circuit of two resisters of 5 ohm and 3 ohm are connected in parallel to each other and this combination is connected to a 9V battery. find the power dissipated in the 3 ohm resistor

Answer 1

(a) Req = 3+2/3×2

= 5/6=1.2Ω

b) V=IR⇒I= R/V

⇒I= 1.2/12 =10A​

(c) 3(10−i)=2i  

(∵ Potential drop in parallel combination are same)

⇒30−3i=2i⇒30=5i⇒i=6A

Current in 2Ω resistor is =i=6A

Current in 3Ω resistor is =10−i=4A

Hope it helps!

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