Question

in an electric circuit two resistors of 2 ohm and 4 ohm are connected in series to a 6 V battery .find the heat dissipated by the 4 ohm resistors in 5 s

Answer 1

Answer:

20 joule

Explanation:

applying kvl on loop

6= 2 i + 4 i

i = 1 Ampere

heat dissipated in 4 ohm resistor in 5 sec

H = i2 r t

H = 1*1*4*5

H= 20 joule