In an electric circuit , two resistors of 2 ohm and 4 ohm are connected in parallel to 6v battery . Calculate the heat dissipated by the 4 ohm resistor in 5 sec
Answers
Answer :
Two identical resistors of resistances 2Ω and 4Ω are connected in parallel to a battery of 4V.
We have to find heat dissipated by the 4Ω resistor in 5s
Concept : Potential difference across each resistor in parallel connection remains same.
Formula of heat dissipated by resistor connected in parallel is given by
- H = V²/R × t
Let's calculate ☃
➝ H = V²/R × t
➝ H = 6²/4 × 5
➝ H = 9×5
➝ H = 45J
Second method [Follow this steps]
- Find current flow in 4Ω resistor using ohm's law.
- Apply H = I²R × t ! You'll get the same answer :D
☞ Heat Dispersed is 45 J
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✭ Two resistors of 2Ω & 4Ω are connected in parallel
✭ Voltage = 6 V
✭ Time = 5 sec
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◈ The heat dispersed?
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So here we shall first find the current through the circuit and for that we shall use the Ohm's law,that is,
Substituting the given values,
➝
➝
➝
➝
So now we shall find the heat dispersed with the help of,
Substituting the values,
➳
➳
➳
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