Physics, asked by Rohityadav799945, 8 months ago

In an electric circuit , two resistors of 2 ohm and 4 ohm are connected in parallel to 6v battery . Calculate the heat dissipated by the 4 ohm resistor in 5 sec

Answers

Answered by Ekaro
26

Answer :

Two identical resistors of resistances 2Ω and 4Ω are connected in parallel to a battery of 4V.

We have to find heat dissipated by the 4Ω resistor in 5s.

Concept : Potential difference across each resistor in parallel connection remains same.

Formula of heat dissipated by resistor connected in parallel is given by

  • H = V²/R × t

Let's calculate

➝ H = V²/R × t

➝ H = 6²/4 × 5

➝ H = 9×5

H = 45J

Second method [Follow this steps]

  • Find current flow in 4Ω resistor using ohm's law.
  • Apply H = I²R × t ! You'll get the same answer :D
Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
2

\huge\sf\pink{Answer}

☞ Heat Dispersed is 45 J

━━━━━━━━━━━━━

\huge\sf\blue{Given}

✭ Two resistors of 2Ω & 4Ω are connected in parallel

✭ Voltage = 6 V

✭ Time = 5 sec

━━━━━━━━━━━━━

\huge\sf\gray{To \:Find}

◈ The heat dispersed?

━━━━━━━━━━━━━

\huge\sf\purple{Steps}

So here we shall first find the current through the circuit and for that we shall use the Ohm's law,that is,

\underline{\boxed{\sf V = IR}}

Substituting the given values,

\sf V = IR

\sf 6 = I\times 4

\sf \dfrac{6}{4} = I

\sf \red{I = 1.5 \ A}

So now we shall find the heat dispersed with the help of,

\underline{\boxed{\sf H = I^2 Rt}}

Substituting the values,

\sf H = 1.5^2 \times 4 \times 5

\sf H = 2.25\times 4 \times 5

\sf \orange{H = 45 \ J}

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