Question

In an electric circuit , two resistors of 2 ohm and 4 ohm are connected in series to a 6v battery . Calculate the heat dissipared by the 4 ohm resistor in 5 seconds

Answer 1

HEY!!

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▶️As the resistors are in series so same will flow through both the resistors.

▶️Equivalent resistance of the circuit is R = 4+2 = 6ohm

▶️Now the current, I= V/R) 6/6= 1A

⏩So the heat dissipated by 4 ohm resistor is, H = I^Rt = 20J

Answer 2

Given :

2 ohm and 4 ohm are connected in series

Potential difference = 6 V

To Find :

The heat dissipated by the 4 ohm resistor in 5 seconds

Solution :

As 2 ohm and 4 ohm resistors are connected in series. Therefore,

Equivalent Resistance ($R_e_q$) = 2 + 4

                                             = 6 ohm

Current flowing through the circuit (I) = $\frac{Potential Difference}{Resistance (R_e_q)}$

                                                                 = $\frac{6}{6}$

                                                                 = 1 A

We know, Heat = I²RT

where, I = current flowing through the circuit

           R = Resistance

           T = Time

∴ The heat dissipated by 4 Ω resistor = I²RT

                                                                = (1)² × 4 × 5

                                                                = 20 J

Therefore, the heat dissipated by 4 Ω resistor in 5 seconds is 20 J.