Question

In an electric circuit with a resistance wire and a cell, the current flowing is l
What would happen to current l if the wire is replaced by another thicker
wire of same material and same length? Give reason.​

Answer 1

Answer:

the current I increases.

Explanation:

The resistance R of a conducting wire is given by the formula :

   R = ρ L / A

where L = length of the conductor, A = cross sectional area

           ρ = resistivity coefficient (constant for a material)

Voltage connected across the resistance = V = constant

So  I = V / R = V A / (ρ L)

If a thicker wire is connected instead of a thinner one, the A increases, and hence the current increases.   Here L is constant.

Answer 2

Answer:

♊♊YOUR ANSWERS♍♍

✍ Current will flow more easily

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EXPLANATION —

Current flow will increase in thick wire as the resistance of a wire is inversly proportional to the square of its diameter.

$R =p \frac{l}{A}$

$R \: = p \frac{l}{\pi {r}^{2} }$

A thick wire has a greater diameter and hence lesser resistance making the current to flow through it more easily.

a thin wire has smaller diameter and hence greater resistance to the flow of current through it.

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