Physics, asked by pc0844718, 2 months ago

In an electric field a test charge 1.2*10-6c experience a force 14.4 N at a point calculate the electric field intensity at the point

Answers

Answered by siddhi1297

0

Answer:

sorry I don't know so sorry and Mark me brainlist

Answered by soorajahirwar2004

0

Answer:

charge =1.2×10^-6

force = 14.4N

E = F/q

12×10^6 N/c

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