Question

in an electric field the work done in bringing a 2 coulomb charge from infinity to a point a is 10 joules and in bringing the same charge to some another point B is 20 joule find the potential difference between two points A and B what would be the work done if the same charge is brought directly from A to B

Answer 1

Work done = 10 joule

Charge = 2 coulomb

Potential of point A VA = 10 J / 2C = 5V

Given work done = 20 Joule 

     Charge = 2  coulomb

Potential of point A VB = 20 J / 2C = 10V

Potential differences between two point A and B is 

V = VB - VA

  = 10V - 5V = 5V

Work done directly from A to B.

Work done = Potential  difference × charge 

                    = 5V × 2C

                     10 Joule.

Answer 2

Answer:

Explanation:

Given :-

Work done = 10 joule

Charge =  2 Coulomb

Potential of point A = V(a) = 10 J/2 C = 5 V

Given :-

Work Done = 20 Joule

Charge = 2 coulomb

Potential of Point B = V(b) = 20 J/2 C = 10 V

Solution :-

Potential Difference between Point A and B = V(a) -  V(b)

⇒ Potential Difference between Point A and B = 10 V - 5 V

⇒ Potential Difference between Point A and B = 5 V

Now, Work done directly from A to B,

Work Done = Potential Difference × Charge

⇒ Work Done = 5 V × 2 C

⇒ Work Done = 10 Joule

Hence, the potential difference between two points A and B is 5 V and the work done if the same charge is brought directly from A to B is 10 Joule.