Question

In an electrical circuit three resistors of 3 Ω, 4 Ω and 5 Ω are connected
in series with a 6V battery. What is the heat dissipated by the 4 Ω resister
in 4 seconds?

Answer 1

Answer:

To count the cells with numeric data, we use the formula COUNT(B4:B16). The COUNT function is fully programmed. It counts the number of cells in a range that contain numbers and returns the result as shown above.

Explanation:

I hope this will help you

Answer 2

Answer:

$i \: = \: \frac{v}{r} \\ = \frac{6}{4} \\ = 1.5 \: ampere$

$t = 4sec$

I = 1.5 A

t = 4 sec

$h \: = i^{2} rt \\ = {1.5}^{2} \times 4 \times 4 \\ \\ = 2.25 \times 16 \\ \\ = \frac{225}{ 100} \times 16 \\ \\ = \frac{225}{25} \times 4 \\ \\ = 9 \times 4 \\ \\ = 36 \: joules$

the heat generated would be 36 joules in 4 sec