Question

In an electrical circuit two resistors of 2 22 and 4 12 respectively
are connected in series to a 6 V battery. The heat dissipated by
the 4 12 resistor in 5 s will be
(a) 5 J
(b) 10 J
(c) 20 J
(d) 30 J​

Answer 1

Answer:

Explanation:

Answer is 20

R=2+4=6

So, I=V/R

=6/6

=1.

So, H=VIT=I2RT

=1*4*5

=20.