Question

In an electrical circuit two resistors of 2 Ω and 4 Ω respectively are connected in parallel to a 6 V battery. The heat dissipated by the 4 Ω resistor in 5 s will be
(a) 45 J
(b) 20 J
(c) 60 J
(d) 35 J

Answer 1

Answer:

Ans. (c) 20J

Explanation: Total resistance of combination = 2ohm+4ohm= 6ohm

Current through the circuit can be calculated as follows:

$i = \frac{v}{r}$

which is =6v/6ohm=1A

Heat dissipation by 4ohm can be calculated as follows:

H=I²Rt = (1.4)² x 4ohm x 5s = 20J

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