In an electrical circuit two resistors of 2 Ω and 4 Ω respectively are connected in series to a 6 V battery. The heat dissipated by the 4 Ω resistor in 5 s will be [NCERT Exemplar Problems]
(a) 5 J
(b) 10 J
(c) 20 J
(d) 30 J
Answers
Answered by
10
Answer:
Explanation:
R1=2 OHMS
R2=4 OHMS
IN SERIES CONNECTION,
R NET=R1+R2=2+4=6 OHMS.
VOLTAGE APPLIED= 6 VOLT
WE KNOW,
V=IR
6=I*6
CURRENT =1A
HEAT DISSIPATED BY 4 OHM RISITOR IN 5 SECONDS,
H=I²RT
H=1*4*5
H=20J.
HOPE IT HELPS.
Answered by
2
Answer:
Answer:i. think your answer is 20J
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