Question

In an electrical circuit two resistors of 29 and 4 O respectively are con
in series to a 6 V battery. The heat dissipated by the 4 resistor
will be​

Answer 1

total current in circut= 6/33=0.181

HEAT=$I^{2}$R

SO on 4 ohm resistor heat dissipated will be

H= $(0.18)^{2}$X4

H= 0.129 J/S