In an electrical circuit two resistors of 8 ohm and 4 ohm are connected in series to a 6 v battery, the heat dessipated by 4 ohms resistor in 5 seconds will be
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Explanation:
The heat dissipated by the 4 ohm resistor in 5 s will be 20 joules. So, the heat dissipated by the 4 ohm resistor in 5 s will be 20 joules. Hence, this is the required solution
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Answer:
5 Joules
Explanation:
Since resistances are in series,
Equivalent resistance of the circuit= 8ohm+4ohm
=12 ohm
Current in circuit(I)=V/R
=6/12 A
=0.5 A
Heat dissipated by 4 ohm resistor
=I^2Rt
=0.5^2 x 4 x 5 Joules
=0.25 x 20 joules
=5 joules
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