Chemistry, asked by ak2340634, 9 hours ago

In an electrolysis experiment ,a current was passed for 5h through two cells connected in series. The first cell contains a solution gold salt and the second cell contains copper sulphate solution 9.85g of gold was deposited in the first cell. If the oxidation number of gold is +3, find the amount of copper deposited on the cathode in the second cell. Also calculate the magnitude of the current in ampere.​

Answers

Answered by rubabsajid000
0

Explanation:

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