Question

In an electromagnetic wave, e = 1.2 sin(2 x 10^6 t -kx)n/c. Find value of intensity of magnetic field.

Answer 1

The value of intensity of magnetic field is $0.4 X 10^{-8}$ A/m

Explanation:

In an electromagnetic wave , $E = 1.2sin(2 X10^{-6} t-kx)$

To find the value ofintensity of magnetic field

we know

        E = $E_0$sin (kx-ωt)

comparing this with the given equation,

         $E_0$ = 1.2

the value of intensity of magnetic field

          $B_0 = \frac{E_{0} }{c}$

           $B_0$ = $\frac{1.2}{3 X 10^{-8} }$

            $B_0$ = $0.4 X 10^{-8}$ A/m