Question

In an electron gun, the electrons are accelerated by the potential V. If e is the charge and m is the mass of an electron, then the maximum velocity of these electrons will be
(a) $\frac{2eV}{m}$
(b) $\sqrt{\frac{2eV}{m}}$
(c) $\sqrt{\frac{2m}{eV}}$
(d) $\frac{V^2}{2em}$

Answer 1

c is the right answer.