Question

In an electronic circuit the P.D.across 3lamp is 30volts and the current through lamp of 0.5A.Find L.the resistance of the lamp IL.the charge flowing through a cross section of the filament in 10second.



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Answer 1

GIVEN:

• potential difference = 30 V

• current flowing= 0.5 A

• time = 10 sec

TO FIND :

• resistance of the lamp

• charge flowing through the cross section in 10 seconds

SOLUTION :

(1)

As per the formula ,

V = I R

R = V / I

R = 30 / 0.5

R = 60 ohms

resistance of the lamp is 60 ohms

(2)

We know that ,

Charge = current × time

Charge = 0.5 × 10

Charge = 5 C