In an elevator moving vertically challenged up with an acceleration g/2 the force exerted on the floor by a passenger of mass M is
(a) Mg
(b) 1/2Mg
(c) zero
(d) 3mg/2
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Answer:
2Mg
Acceleration =g
Force exerted on the floor by Y
a
Mass=M
Upward=Mg
Downward=Mg
Total =2Mg
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