Math, asked by preetytripathi18, 3 months ago

in an entrance test 22 questions are set. In how many ways can you choose 18 questions to answer?​

Answers

Answered by arpeettribhuwan
0

Answer:

Simply, either you choose 8 questions out of 10 to answer or 2 questions out of 10 not to answer. The answer is same and it is 10C2. And this is solved as 10!/(8!×2!). The answer is 45. Always when you get a question to select r things for n things, the answer is nPr. Which is again n!/{r!×(n-r)!}.

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