Question

In an envelope there are some 5 rupee notes and some 10 rupee notes. Total amount of these notes is Rupees 350.The number of 5 rupee notes are less by 10 than twice the number of 10 rupee notes. Then find the number of 5 rupee notes and 10 ruoee notes. Someone plz help me solve this simentaneous equation very urgent.

Answer 1

No. Of Rs.5 note = x

No. Of Rs. 10 note = y

5x + 10y = 350

x = 2y - 10

x = 30

y = 20

Answer 2

HELLO..
HERE IS YOUR ANSWER ...

Let the notes be = x
so no.₹5 notes = 5x
no. of ₹10 notes =10x

ACCORDING TO QUESTION ₹5 NOTES ARE TWICE THEN ₹10 NOTES AND LESS BY TEN MEANS 5(2x-10)

AND SUM OF BOTH ₹5 AND ₹10 NOTES IS ₹350 SO.

A/q

5(2x-10)+10x = 350
10x-50+10x= 350
20x= 350+50
x= 400/20
x= 20

So no. of ₹ 10 notes = 20
no. of ₹5 notes = 2(20)-10➡40-10➡30

--------------------------------------------------------

$\mathbb{\huge{\pink{HOPE\: IT \:HELPS }}}$