Biology, asked by saumyasaxena7073, 1 month ago

In an enzymatic reaction of maltase, the disaccharide maltose is hydrolyzed to glucose. In an
experiment, an inhibitor X was added to the reaction. The addition of the inhibitor brought about a
change in the activity of the enzyme. When the substrate concentration was 0.125 mM, the initial
velocity was 0.10 mM per minute. However, Vo / Initial velocity changed to 0.25 mM per minute
when the substrate concentration was 0.50 mM. Hence, calculate the
Km
of the reaction.​

Answers

Answered by abhishekpenumarla
0

Answer:

Correct option is

B

Maltose → Glucose

Reaction catalysed by enzyme 'Maltase' is the conversion of Maltose→Glucose.

Maltose is a disaccharide and on hydrolysis, it gives glucose.

Maltose(C

12

H

22

O

11

)

Maltase

hydrolysis

Glucose(C

6

H

12

O

6

)+Glucose(C

6

H

12

O

6

).

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