In an equilateral glass prism, for two angles of incidence, differing by 10°, the angle of deviation is found to be 40°, find these angles of incidence.
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Answer: 45° and 55°
Explanation:
For a prism, the angle of deviation is given by:
δ=i₁+i₂-A
where A is the angle of prism.
A=60° (equilateral prism)
Angle of deviation, δ=40° (given)
i₁, i₂ are the angles of incidences
i₁-i₂=10°⇒i₁=10°+i₂
i₁+i₂=δ+A
⇒i₁+i₂=40°+60°= 100°
Substitute the value of i₁
10°+i₂+ i₂= 100°⇒2 i₂=90°⇒i₂=45°
i₁=100-45°=55°
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