Question

In an equilateral triangle ABC, AB= (3X + 1 ) cm, BC=(2x + 3y + 5)cm, and AC= ( x+9y+6)cm. Find the value of x and y .

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The value of x is 7 and the value of y is 1.

Step-by-step explanation:

Given information: In an equilateral triangle ABC, AB= (3X + 1 ) cm, BC=(2x + 3y + 5)cm, and AC= ( x+9y+6)cm.

We need to find the value of x is y.

All sides of an equilateral triangle are congruent.

$AB=BC$

$3x+1=2x+3y+5$

$x-3y=4$             .... (1)

$AB=AC$

$3x+1=x+9y+6$

$2x-9y=5$           .... (2)

Multiply equation (1) by 3 and subtract from equation (2).

$2x-9y-3(x-3y)=5-3(4)$

$2x-9y-3x+9y=5-12$

$-x=-7$

$x=7$

Substitute x=7 in equation (1).

$(7)-3y=4$

$-3y=4-7$

$-3y=-3$

$y=1$

Therefore, the value of x is 7 and the value of y is 1.

#Learn more

X+5y=7 and 2x+y=6 solved the equation​.

https://brainly.in/question/11700187