in an equilateral triangle ABC ,AD is an altitude drawn from A on side BC .Prove that 3AB^2=4AD^2.
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Answered by
34
Answer:
Step-by-step explanation:
In ∆ABC,
(AB)^2=AD^2+BD^2
AB^2=AD^2+(1/2bc)^2
Step-by-step explanation:
In ∆ABC,
(AB)^2=AD^2+BD^2
AB^2=AD^2+(1/2bc)^2
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kajal1902:
thank you so much dear
Answered by
9
Answer:
Step-by-step explanation:
By the formula of height of equilateral
triangle
AD=3^-2 × AB/2
2AD=3^-2×AB
By squaring both sides,we get
4AD^2=3AB^2
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