in an equilateral triangle ABC,AD is drawn perpendicular to BC meeting at A. prove that ADsquare=3BDsquare
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Here let side of triangle is a
per. AD^2 = 3a^2 / 4.
BD^2 = a^2 / 4.
on finding ratio you will get.
AD^2 = 3BD^2.
hope it may help....if any problem then discuss here.
per. AD^2 = 3a^2 / 4.
BD^2 = a^2 / 4.
on finding ratio you will get.
AD^2 = 3BD^2.
hope it may help....if any problem then discuss here.
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