in an equilateral triangle ABC AD is perpendicular to BCthen find
AD square / BC square
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Answer:
Hello There,
This is your answer.
Step-by-step explanation:
ABC is an equilateral triangle
Thus, AB = AC = BC = 2a
We know that in an equilateral triangle, the altitude is also the median
Thus, AD is the median
Thus, CD = BC/2 = 2a/2 = a
In triangle ADC, angle D = 90
AC^2 = AD^2 + CD^2
= AD^2 = AC^2 - CD^2
= (2a)^2 - a^2
= 4a^2 - a^2
= 3a^2
AD = Root 3a
AD square / BC square = 3a^2 / 4a^2
HOPE IT HELPS YOU!!!
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