In an equilateral triangle ABC,AD us perpendicular to BC then find AD square
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here ABC is equilateral triangle
let a be side of triangle
we know perpendicular from a vertex to its side of equilateral triangle bisects the side
so DC=a/2
using Pythagoras. thereom
a^-(a/2)^2=DC^2
3a^2/4=DC
it is your answer
hope it will help you
let a be side of triangle
we know perpendicular from a vertex to its side of equilateral triangle bisects the side
so DC=a/2
using Pythagoras. thereom
a^-(a/2)^2=DC^2
3a^2/4=DC
it is your answer
hope it will help you
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