Question

IN AN EQUILATERAL TRIANGLE , ABC ,D IS A POINT ON SIDE BC SUCH THAT BD=
$\frac{1}{3}$BC
bc prove that 9AD²=7AB²​

Answer 1

$\huge\green{given}$

Equilateral triangle ABCD is a point an BC

$Such \: that \: BD = \frac{1}{3} BC$

$\huge\green{to \: prove}$

$9 {ad}^{2} = 7 {ab}^{2}$

THAN THE DRAW IN THE PIC↑↑↑

$\huge\red{proof}$

All sides of equilateral triangle is equal

AB = BC = AC

Let AB = BC = AC =

❤ʜᴏᴘᴇ ɪᴛ's ʜᴇʟᴘғᴜʟ❤

Answer 2

Answer:

Check your answer please