Question

In an equilateral triangle ABC, if AD perpendicular to BC, then prove that 3AB*2=4AD*2

Answer 1

The answer is in the below attachment. Plz mark it as brainliest.....

Answer 2

In equilateral triangle ABC, AB=BC=CA
since,AD is perpendicular drawn on side BC,
BD=DC=(1/2)×BC
NOW,in ∆ABC, angle ADC =90°
SO,
CA^2=AD^2+DC^2
4(DC^2) =AD^2+DC^2(since,CA=BC)
AD^2=3DC^2
hence,proved