Math, asked by sshekharapr, 18 days ago

In an equilateral triangle ABC, P is a point in such an way that PA^2 = PB^2 + PC^2 then the value of angleBPC is (A) 120° ,(B) 150° ,(C) 145° ,(D) 135° .​

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Answered by ishitasahai0999
1

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