Question

In an equilateral triangle ABC , point D is the midpoint of side BC . prove that 4AD^ = 3BC^
.
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please give me a right answer ​

Answer 1

Answer:

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Step-by-step explanation:

Let AB,BC,ACBE equal

to a

D is the midpoint of

BC.

By Pythagoras theorem

AB

2

=AD

2

+BD

2

a

2

=AD

2

+(a/2)

2

a

2

−

4

a

2

=AD

2

4

3a

2

=AD

2

But AB =a

3AB

2

=4AD

2

∴ 4AD

2

=3AB

2