Question

In an equilateral triangle ABC point P, Q, R divides sides BC, PQ, and AB in ratio 1:2 and area of triangle PQR is 60 square centimetres, then find the area of triangle ABC?

Answer 1

Answer:

240 sq.cm

Step-by-step explanation:

In an equilateral triangle A,B,C point P,Q,R divides sides BC,CA and AB in the ratio 1:2 and the area of triangle PQR is 60 sq.cm

we know that the area of the triangle formed by joining the mid points of the sides of a given triangle PQR is 1/4th of the area of the given triangle ABC

that is the Area of the triangle ABC= 4×(the area of the triangle PQR)=4×60=240 sq.cm