Question

In an equilateral triangle of seg PSis perpendicular to seg QR. Then PS²?​

Answer 1

Answer:

PT be the perpendicular from P on QR. Hence,QT=

2

1

QR

ST=QR(

2

1

−

3

1

)=

6

1

QR

PS

2

=PT

2

+ST

2

also,PT=QTtan60

∘

PT=

3

QT

PS

2

=3QT

2

+

36

QR

2

PS

2

=

4

3QR

2

+

36

QR

2

PS

2

=

36

28QR

2

=

9

7QR

2

QR=PQ

9PS

2

=7PQ

2