Question

in an equilateral triangle of side 24 c find the length. of the altitude

Answer 1

ALTITUDE OF TRIANGLE ===

$\frac{ \sqrt{3} }{2} \times \: side$

$= > \frac{ \sqrt{3} }{2} \: \times 24$

$= > 12 \sqrt{3}$ cm

Answer 2

Given that side of equilateral triangle is 24 cm

So area = √3/4 × side²

=> area = √3/4 × 24²

=> area = √3/4 × 576

=> area = 144√3


But we also know that area of a ∆ =

1/2 × base × altitude

=> 1/2 × base × altitude = area

Area = 144√3

=> 1/2 × 24 × altitude = 144√3

=> 12 × altitude = 144√3

=> altitude = 144√3/12

=> altitude = 12√3


Your answer :- 12√3 = 20.78 cm (approx)