Question

In an equilateral triangle of side 24cm find the length of altitude​

Answer 1

Answer:

Step-by-step explanation:

In a equilateral triangle length of altitude =$\sqrt{side^{2}+(side/2)^{2} }$

hens;

altitude=$\sqrt{24^{2}+12^{2}}$

=$12\sqrt{3}$cm

Answer 2

Answer: 12$\sqrt{3}$ cm

Step-by-step explanation:

Let ABC be an equilateral triangle of side 24 cm and AD is altitude which is also a perpendicular bisector of side BC

Hence       BD = $\frac{BC}{2}$ = $\frac{24}{2}$ = 12

∴                AD = $\sqrt{((AD)^{2} - (BD)^{2} }$

                        = $\sqrt{(24)^{2} - (12)^{2} }$

                        = $\sqrt{576 - 144}$  

                        =  $\sqrt{432}$

                      AD  = 12$\sqrt{3}$ cm

The length of the altitude is 12$\sqrt{3}$ cm