Question

. In an equilateral triangle of side 3 √3 cm. Find the length of the altitude.​

Answer 1

Step-by-step explanation:

Given

side of an equilateral triangle

ABC=33cm

AB=BC−AC=33cm

Let AD=h (altitude)

BD=21B (Altitude bisect the base)

BD=21.33=33/2 cm

AB2=AD2+BD2

(33)2=(h)2+(33/2)2

⇒27=h2+27/4

⇒h2=27−27/4

⇒h2=(4.27−27)/4

⇒h2=108−27/4

⇒h2=81/7

⇒h=81/4

⇒h=9/2

⇒h=4.5cm

Hence, the length of the altitude h is 4.5 cm