Question

in an equilateral triangle ∆PQR seg PS⊥ side QR , PQ = 6 ,then Ps​

Answer 1

Answer:

PS=3√3

Step-by-step explanation:

Given, PQ=6

Find , PS=?

ΔPQR is an equilateral triangle

So, PQ=PR=QR=6

PS is perpendicular on QR,

So, QS=SR

QR=QS+SR

6=QS+QS

6=2QS

6/2=QS

QS=3

So , QS=SR=3

In ΔPQS,

By Pythagoras theorem ~

PQ^2=PS^2+QS^2

[6]^2=PS^2+[3]^2

36=PS^2+9

36-9=PS^2

PS=√27

PS=3√3

The value of PS is 3√3.

I hope this answer is helpful for you.