In an equilateral triangle prove that the centroid and the Circumcircle of the triangle coincide.
•Hint:-
Prove that the medians are perpendicular bisectors of the sides of triangle.
___
•No Spamming Please
Answers
In this question we have to prove that centroid and circumcircle of triangle coincidence which means that centroid G is equidistant from vertices. Which we can simplify prove by using congruency.
First we should know the property of equilateral ∆
- All sides are equal in equilateral∆
- Also all the angles are of 60°
Also we know that median of a triangle divides the side in equal length.
So:-
- BD=DC
- BF=AF
- AE=EC
So let's apply congruency rule in ∆BCF and ∆BCE
BF=CE (Proved above)
angle B=Angle C ( each 60°)
BC=BC (Common)
So ∆BCF is congruent to ∆BCE (by SAS)
BE=CF( by C.P.C.T).....(1)
________________
Now apply congruency rule in ∆AFC and ∆ADC
AF=DC (Proved above)
Angle A =Angle C ( each 60°)
AC=AC (Common)
So ∆AFC is congruent to ∆ADC (By SAS)
AD=CF (by C.P.C.T)......(2)
________________
From (1) and (2) equations
BE=CF=AD.....(3)
As we know that centroid of the triangle (G) divide the median in the ratio 2:3.
So on dividing the equation (3) by 2/3 we get:-
GB=GC=GA
Now we can say that centroid G is equidistant from the three vertices of ∆ ABC.
Hence it is proved that G is centroid as well as centre of circumcircle of equilateral triangle or Centroid and circle are coincide.
________________
★What is centroid?
➠The point at which three medians of the triangle meet is called it's centroid.
★What is circumcircle?
➠It is the special type of circle in which triangle is inscribed.
★What is C.P.C.T.?
➠Corresponding part of congruent triangle.
Answer:
Given: An equilateral triangle ABC in which D, E and F are the mid-point of sides BC, CA and AB respectively. To prove: the centroid and circumcentre are coincident. Read more on Sarthaks.com - https://www.sarthaks.com/268596/equilateral-triangle-prove-that-the-centroid-centre-circum-circle-circumcentre-coincide