In an equilateral triangle, prove that the square of any one side is equal to four times of its height.
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Answer:
3a=4(AD)^2
Step-by-step explanation:
(AB)^2=(AD)^2+(1/2a)^2
a^2=(AD)^2+a^2/4
a^2-a^2/4=AD^2
3a^2=4AD^2
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