In an equilateral triangle the cirum radius is n times inradius then n is equal to
Answers
Answered by
0
For a given perimeter, an equilateral triangle uniquely maximizes the inradius and minimizes the circumradius. Hence it is the only triangle in which R=2r, and all other triangles have R>2r.
Let a,b,c are the sides of a triangle, A= area of the triangle, s= semi-perimeter.
R=abc/4A,r=A/s
We have to show R≥2r.
The relation abc/4A≥2A/s holds
if abc≥8A/2s
if abc≥8(s−a)(s−b)(s−c)
if abc≥(b+c−a)(c+a−b)(a+b−c)
This is true for all triangles.
When a=b=c, the equality holds.This is the case of an equilateral triangle.
So R=2r
Similar questions