In an equilateral triangles ABC, AD is an altitude than 4AD² is equal to?
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Answer :
3AC²
Step-by-step explanation :
Let the side of the triangle be a units
Given that ∆ABC is equilateral.
So AB = BC = CA = a units
AD is the Altitude say of height 'h' units
In an equilateral triangle the altitude(AD) bisects BC.
Therefore, BD =DC = a/2
By using Pythagoras theorem,
(a/2)² + h² = a²
a²/4 + h² =a²
h² = a² - a²/4
h² = (4a² -a²)/ 4
h² = 3a²/4
4h² = 3a²
4AD² = 3AC²
HOPE THIS HELPED YOU :-)
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