Question

in an equiletral triangle abc of sides 6cm,perpendicular form vertex a to base B is 4cm find the area of triangle. also find the height of the perpendicular from the vertex c to the opposite base​

Answer 1

Step-by-step explanation:

Answer

Here AD=12cm

∴ In ΔABD

∠B=60

o

∠AOD=90

o

∠BAD=30

o

∴sin60

o

=

AB

AD

∴

2

3

=

AB

12

∴AB=

3

24

∴AB=8

3

cm

∴ Perimeter of triangle=8

3

×3

=24

3

cm

∴ Area of triangle =

4

3

×(side)

2

cm

2

∴ Area of triangle=

4

3

×(8

3

)

2

∴ Area of triangle=

4

3

×64×3

∴ Area =46

3

.