Question

in an exam, 27% students failed in Maths,24% students failed in English and 20% students failed in
both the subjects.
1.
Find the percentage of students who failed in any of the subjects.
2.
Find the percentage of students who failed in both the subjects.
3.
If 414 students passed in both the subiecto find the total number of students.​

Answer 1

Solution:-

Percentage of students failed in Maths = 27%

Percentage of students failed in English = 24%

Therefore, Percentage of students failed in any of the subjects=> (27+24)%= 51%

Percentage of students failed in both of the subjects= 20%

Therefore, Percentage of students failed in Maths only=> (27-20)%= 7%

And percentage of students failed in English only=> (24-20)%= 4%

Hence, Total percentage of students failed=> (7 + 4 + 20)%= 31%

And total percentage of students passed=> (100-31)%= 69%

No. of students who passed in both of subjects= 414

Let the total no. of students be 'x'

$69\% \: of \: x \: = 414$

$= > \dfrac{69}{100} \times x = 414$

$= > \dfrac{69x}{100} = 414$

$= > x = \dfrac{414 \times 100}{69}$

$= > x = 600$

Hence, Total no. of students is 600.

Answer:-

1] Percentage of students who failed in any of the subjects= 51%

2] Percentage of students who failed in both the subjects= 20%

3] Total number of students= 600

Answer 2

Hey here is your answer