Question

in an exam a student got 28% of total marks and failed as he got 80 marks less than the total required. Another student passed by scoring 38% of the total marks,when he had scored 20 marks more than the required total. how many marks were required for passing?​

Answer 1

Answer:

passing marks is= 28% + 80marks

passing marks is= 38% -20marks

so ..

28%+ 80=38% -20

80+20 = 38%-28%

100=10%

then 100%=1000marks

so passing marks will be

28% of 1000+80 marks

=280+80

=360

... if I'm good marks as brilliant ☺️

Answer 2

Passing marks were 360.

Step-by-step explanation:

Let the total marks be 'x'.

in an exam a student got 28% of total marks and failed as he got 80 marks less than the total required

It means to get the passing marks, his expression would be

$\dfrac{28}{100}\times x+80\\\\=0.28x+80$

. Another student passed by scoring 38% of the total marks,when he had scored 20 marks more than the required total.

To get passing marks, his expression would be

$\dfrac{38}{100}x-20\\\\0.38x-20$

So, both are passing marks now,

Therefore,

$0.28x+80=0.38-20\\\\80+20=0.38x-0.28x\\\\100=0.1x\\\\x=\dfrac{100}{0.1}=1000$

Passing marks would be

$0.28\times 1000+80\\\\=280+80\\\\=360$

Hence, Passing marks were 360.

# learn more:

A student scored 32% marks in an examination and failed by 12 marks another student scored 42% marks and got 28% marks more than the minimum marks required to pass find the maximum marks and the pass percentage of marks

https://brainly.in/question/2664101