Question

in an exam of 3/8 students passed, 6/11 students failed and the rest were absent. what is the ratio of the number of students who were absent to the total number of students?

Answer 1

Answer:

7 : 88

Step-by-step explanation:

Let the total number of students be a.

 So,

Passed students : 3/8 of a

                   ⇒ 3a / 8

Failed students : 6/11 of a

                   ⇒ 6a / 11

Total students = a

⇒ passed stu. + failed. stu + absent stu. = a

⇒ ( 3a / 8 ) + ( 6a / 11 ) + abs. stu. = a

⇒ abs. stu = a - ( 3a / 8 ) - ( 6a / 11 )

⇒ abs. stu = ( 88a - 33a - 48a ) / 88

             ⇒  7a / 88

Hence,

⇒ Req. ratio = ( 7a / 88 ) / a

             ⇒ ( 7a / 88a )

             ⇒ 7 / 88

             ⇒ 7 : 88

Answer 2

Step-by-step explanation:

Aloha !

$\text { This is Twilight Astro}$

Given,

⅜ students are passed and 6/11 students are failed . And remaining students are absent .

Let A be some integer.

NOW,.

Total no of students in class = ⅜A+6/11A+ absent students.

So,

A= ⅜A+6÷11A+absent students.

absent students= A-⅜A-6÷11A

absent students= 88A-3×11A-6×8A/88

absent students=88A-33A-48A/88

absent students= 55A-48A/88

absent students=7A/88.

Such that,..

absent students=7A/88÷A

absent students=7/88

Thank you

@ Twilight Astro ✌️☺️

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