In an exam ravi got 28% Mark's failed by 14 marks.sami get 48% Mark's nd passed by 16 Mark's find the pass Mark's
Answers
Question :
In an exam Ravi got 28% marks, failed by 14 marks. Sami get 48% marks and passed by 16 marks. Find the pass marks.
Answer:
The pass marks is 56.
Given:
Ravi got 28% marks.
Ravi failed by 14 marks.
Sami get 48% marks.
Sami passed by 16 marks.
To find:
The pass marks of the exam.
Explanation:
Let, the total marks of the exam be, 'n'.
Ravi got 28% marks.
∴ Ravi got ( n×28/100)
= 28n/100 marks
Sami get 48% marks.
∴ Sami got (n×48/100)
= 48n/100 marks.
Ravi failed by 14 marks.
Sami passed by 16 marks.
∴ According to the problem:
(48n/100) - (28/100) = (16+14)
⇒ (48n - 28n)/100 = 30
⇒ 20n =(30×100)
⇒ n =(30×100)/20
⇒ n = (30×5)
⇒ n = 150
∴ The total marks is 150.
Case-1:
Ravi got 28% marks.
∴ Ravi got_
(150×28/100)
=(3×28/2)
= (3×14)
= 42 marks.
Ravi failed by 14 marks.
∴ The pass marks is_
(42+14)
= 56 marks.
Case-2:
Sami get 48% marks.
∴ Sami got_
(150×48/100)
= (3×48/2)
=(3×24)
= 72 marks.
Sami passed by 16 marks.
∴ The pass marks is_
(72-16)
= 56 marks.
Since, in both the cases we get the pass marks is 56.
∴ The pass marks is 56.